Base | Representation |
---|---|
bin | 10011001011010101010… |
… | …011100111100000011001 |
3 | 11122222120102222101202011 |
4 | 103023111103213200121 |
5 | 133042413200312022 |
6 | 2445223504305521 |
7 | 164132161655125 |
oct | 23132523474031 |
9 | 4588512871664 |
10 | 1317838682137 |
11 | 46898a6420aa |
12 | 1934a56122a1 |
13 | 9736ba95463 |
14 | 47ad87c2585 |
15 | 24430065977 |
hex | 132d54e7819 |
1317838682137 has 2 divisors, whose sum is σ = 1317838682138. Its totient is φ = 1317838682136.
The previous prime is 1317838682131. The next prime is 1317838682219. The reversal of 1317838682137 is 7312868387131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1259593203856 + 58245478281 = 1122316^2 + 241341^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1317838682137 is a prime.
It is not a weakly prime, because it can be changed into another prime (1317838682131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658919341068 + 658919341069.
It is an arithmetic number, because the mean of its divisors is an integer number (658919341069).
Almost surely, 21317838682137 is an apocalyptic number.
It is an amenable number.
1317838682137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1317838682137 is an equidigital number, since it uses as much as digits as its factorization.
1317838682137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8128512, while the sum is 58.
The spelling of 1317838682137 in words is "one trillion, three hundred seventeen billion, eight hundred thirty-eight million, six hundred eighty-two thousand, one hundred thirty-seven".
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