Base | Representation |
---|---|
bin | 111101010111100000… |
… | …0100010010001001001 |
3 | 110121011100001101021211 |
4 | 1322233000202101021 |
5 | 4124344001001131 |
6 | 140312525333121 |
7 | 12343521323365 |
oct | 1725700422111 |
9 | 417140041254 |
10 | 131785172041 |
11 | 50987326326 |
12 | 2165a7071a1 |
13 | c5729a2653 |
14 | 65426022a5 |
15 | 366493d5b1 |
hex | 1eaf022449 |
131785172041 has 2 divisors, whose sum is σ = 131785172042. Its totient is φ = 131785172040.
The previous prime is 131785172027. The next prime is 131785172117. The reversal of 131785172041 is 140271587131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106510849600 + 25274322441 = 326360^2 + 158979^2 .
It is a cyclic number.
It is not a de Polignac number, because 131785172041 - 211 = 131785169993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131785171985 and 131785172003.
It is not a weakly prime, because it can be changed into another prime (131785172021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65892586020 + 65892586021.
It is an arithmetic number, because the mean of its divisors is an integer number (65892586021).
Almost surely, 2131785172041 is an apocalyptic number.
It is an amenable number.
131785172041 is a deficient number, since it is larger than the sum of its proper divisors (1).
131785172041 is an equidigital number, since it uses as much as digits as its factorization.
131785172041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47040, while the sum is 40.
The spelling of 131785172041 in words is "one hundred thirty-one billion, seven hundred eighty-five million, one hundred seventy-two thousand, forty-one".
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