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131800842643 is a prime number
BaseRepresentation
bin111101010111111110…
…0010100000110010011
3110121012102112112022111
41322233330110012103
54124412003431033
6140314245250151
712344101451311
oct1725774240623
9417172475274
10131800842643
1150995159938
1221663a03957
13c575ccb2b2
1465447210b1
153665ed67cd
hex1eaff14193

131800842643 has 2 divisors, whose sum is σ = 131800842644. Its totient is φ = 131800842642.

The previous prime is 131800842629. The next prime is 131800842661. The reversal of 131800842643 is 346248008131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131800842643 - 217 = 131800711571 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131800842596 and 131800842605.

It is not a weakly prime, because it can be changed into another prime (131800842673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65900421321 + 65900421322.

It is an arithmetic number, because the mean of its divisors is an integer number (65900421322).

Almost surely, 2131800842643 is an apocalyptic number.

131800842643 is a deficient number, since it is larger than the sum of its proper divisors (1).

131800842643 is an equidigital number, since it uses as much as digits as its factorization.

131800842643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 110592, while the sum is 40.

The spelling of 131800842643 in words is "one hundred thirty-one billion, eight hundred million, eight hundred forty-two thousand, six hundred forty-three".