Base | Representation |
---|---|
bin | 111101011001000010… |
… | …0010010000001101111 |
3 | 110121021220121101110022 |
4 | 1322302010102001233 |
5 | 4130000120020433 |
6 | 140322001232355 |
7 | 12345013432124 |
oct | 1726204220157 |
9 | 417256541408 |
10 | 131836485743 |
11 | 50a03294046 |
12 | 216739326bb |
13 | c5804ca9a1 |
14 | 654935c74b |
15 | 36691c7698 |
hex | 1eb211206f |
131836485743 has 4 divisors (see below), whose sum is σ = 133116451728. Its totient is φ = 130556519760.
The previous prime is 131836485719. The next prime is 131836485757. The reversal of 131836485743 is 347584638131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131836485743 - 210 = 131836484719 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131836485343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 639982838 + ... + 639983043.
It is an arithmetic number, because the mean of its divisors is an integer number (33279112932).
Almost surely, 2131836485743 is an apocalyptic number.
131836485743 is a deficient number, since it is larger than the sum of its proper divisors (1279965985).
131836485743 is a wasteful number, since it uses less digits than its factorization.
131836485743 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1279965984.
The product of its digits is 5806080, while the sum is 53.
The spelling of 131836485743 in words is "one hundred thirty-one billion, eight hundred thirty-six million, four hundred eighty-five thousand, seven hundred forty-three".
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