Base | Representation |
---|---|
bin | 10011001100011111111… |
… | …111011001100111011001 |
3 | 11200002210202200221211221 |
4 | 103030133333121213121 |
5 | 133102444432023221 |
6 | 2445552104252041 |
7 | 164205215140264 |
oct | 23143777314731 |
9 | 4602722627757 |
10 | 1319091673561 |
11 | 469472952102 |
12 | 193795171021 |
13 | 9750b5517bc |
14 | 47bb6d87cdb |
15 | 244a506c541 |
hex | 1331ffd99d9 |
1319091673561 has 2 divisors, whose sum is σ = 1319091673562. Its totient is φ = 1319091673560.
The previous prime is 1319091673457. The next prime is 1319091673577. The reversal of 1319091673561 is 1653761909131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1166410800025 + 152680873536 = 1080005^2 + 390744^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1319091673561 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1319091673499 and 1319091673508.
It is not a weakly prime, because it can be changed into another prime (1319091673961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659545836780 + 659545836781.
It is an arithmetic number, because the mean of its divisors is an integer number (659545836781).
Almost surely, 21319091673561 is an apocalyptic number.
It is an amenable number.
1319091673561 is a deficient number, since it is larger than the sum of its proper divisors (1).
1319091673561 is an equidigital number, since it uses as much as digits as its factorization.
1319091673561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 918540, while the sum is 52.
The spelling of 1319091673561 in words is "one trillion, three hundred nineteen billion, ninety-one million, six hundred seventy-three thousand, five hundred sixty-one".
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