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131913402193 is a prime number
BaseRepresentation
bin111101011011010100…
…1101100011101010001
3110121111021100010222201
41322312221230131101
54130124312332233
6140333350003201
712346636263256
oct1726651543521
9417437303881
10131913402193
1150a42749561
1221695646501
13c59341b691
14655566142d
153670d1c77d
hex1eb6a6c751

131913402193 has 2 divisors, whose sum is σ = 131913402194. Its totient is φ = 131913402192.

The previous prime is 131913402163. The next prime is 131913402311. The reversal of 131913402193 is 391204319131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125243086609 + 6670315584 = 353897^2 + 81672^2 .

It is an emirp because it is prime and its reverse (391204319131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131913402193 - 25 = 131913402161 is a prime.

It is a super-2 number, since 2×1319134021932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131913402133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65956701096 + 65956701097.

It is an arithmetic number, because the mean of its divisors is an integer number (65956701097).

Almost surely, 2131913402193 is an apocalyptic number.

It is an amenable number.

131913402193 is a deficient number, since it is larger than the sum of its proper divisors (1).

131913402193 is an equidigital number, since it uses as much as digits as its factorization.

131913402193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 37.

The spelling of 131913402193 in words is "one hundred thirty-one billion, nine hundred thirteen million, four hundred two thousand, one hundred ninety-three".