Base | Representation |
---|---|
bin | 111101011101010010… |
… | …0110100001010010001 |
3 | 110121122212012122100121 |
4 | 1322322210310022101 |
5 | 4130243140410024 |
6 | 140344100550241 |
7 | 12351365650501 |
oct | 1727244641221 |
9 | 417585178317 |
10 | 131979231889 |
11 | 50a7692136a |
12 | 216b36b2381 |
13 | c5a3c59c6b |
14 | 65602b9a01 |
15 | 36769c28e4 |
hex | 1eba934291 |
131979231889 has 2 divisors, whose sum is σ = 131979231890. Its totient is φ = 131979231888.
The previous prime is 131979231871. The next prime is 131979232003. The reversal of 131979231889 is 988132979131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98585324289 + 33393907600 = 313983^2 + 182740^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131979231889 is a prime.
It is not a weakly prime, because it can be changed into another prime (131979231829) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65989615944 + 65989615945.
It is an arithmetic number, because the mean of its divisors is an integer number (65989615945).
Almost surely, 2131979231889 is an apocalyptic number.
It is an amenable number.
131979231889 is a deficient number, since it is larger than the sum of its proper divisors (1).
131979231889 is an equidigital number, since it uses as much as digits as its factorization.
131979231889 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5878656, while the sum is 61.
The spelling of 131979231889 in words is "one hundred thirty-one billion, nine hundred seventy-nine million, two hundred thirty-one thousand, eight hundred eighty-nine".
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