Base | Representation |
---|---|
bin | 11110000000100110110110… |
… | …000100000000000000000000 |
3 | 122022022110110111001212200000 |
4 | 132000212312010000000000 |
5 | 114244402344230300142 |
6 | 1144412111242400000 |
7 | 36541315240161600 |
oct | 3600466604000000 |
9 | 568273414055600 |
10 | 131983104540672 |
11 | 390657a17a2390 |
12 | 12977262800000 |
13 | 5884c51699638 |
14 | 2484032bc2c00 |
15 | 103d2b414e14c |
hex | 7809b6100000 |
131983104540672 has 2268 divisors, whose sum is σ = 518485285504368. Its totient is φ = 33175476633600.
The previous prime is 131983104540671. The next prime is 131983104540673. The reversal of 131983104540672 is 276045401389131.
131983104540672 is a `hidden beast` number, since 1 + 3 + 1 + 9 + 8 + 31 + 0 + 4 + 540 + 67 + 2 = 666.
It is an interprime number because it is at equal distance from previous prime (131983104540671) and next prime (131983104540673).
It is a tau number, because it is divible by the number of its divisors (2268).
It is a super-3 number, since 3×1319831045406723 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is not an unprimeable number, because it can be changed into a prime (131983104540671) by changing a digit.
It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 4257519501297 + ... + 4257519501327.
It is a 1-persistent number, because it is pandigital, but 2⋅131983104540672 = 263966209081344 is not.
Almost surely, 2131983104540672 is an apocalyptic number.
131983104540672 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131983104540672, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (259242642752184).
131983104540672 is an abundant number, since it is smaller than the sum of its proper divisors (386502180963696).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131983104540672 is an frugal number, since it uses more digits than its factorization.
131983104540672 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142 (or 54 counting only the distinct ones).
The product of its (nonzero) digits is 4354560, while the sum is 54.
The spelling of 131983104540672 in words is "one hundred thirty-one trillion, nine hundred eighty-three billion, one hundred four million, five hundred forty thousand, six hundred seventy-two".
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