Base | Representation |
---|---|
bin | 1100000000010101111100… |
… | …1110000001001100100100 |
3 | 1201201220120221000112200010 |
4 | 3000011133032001030210 |
5 | 3212232131143323134 |
6 | 44024002212450220 |
7 | 2531446045551144 |
oct | 300053716011444 |
9 | 51656527015603 |
10 | 13200032011044 |
11 | 422a113a452aa |
12 | 1592308019970 |
13 | 7499b0804a28 |
14 | 338c5647a924 |
15 | 17d56a830ce9 |
hex | c015f381324 |
13200032011044 has 12 divisors (see below), whose sum is σ = 30800074692464. Its totient is φ = 4400010670344.
The previous prime is 13200032011039. The next prime is 13200032011057. The reversal of 13200032011044 is 44011023000231.
It is a tau number, because it is divible by the number of its divisors (12).
It is a self number, because there is not a number n which added to its sum of digits gives 13200032011044.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550001333782 + ... + 550001333805.
Almost surely, 213200032011044 is an apocalyptic number.
It is an amenable number.
13200032011044 is an abundant number, since it is smaller than the sum of its proper divisors (17600042681420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13200032011044 is a wasteful number, since it uses less digits than its factorization.
13200032011044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1100002667594 (or 1100002667592 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 13200032011044 its reverse (44011023000231), we get a palindrome (57211055011275).
The spelling of 13200032011044 in words is "thirteen trillion, two hundred billion, thirty-two million, eleven thousand, forty-four".
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