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13200111031212 = 22337473474212543
BaseRepresentation
bin1100000000010110001111…
…1011011101001110101100
31201201220210102201011222000
43000011203323131032230
53212232311410444322
644024014114252300
72531451025323510
oct300054373351654
951656712634860
1013200111031212
11422a154607326
12159232a587090
137499c3cb1121
14338c62b6a140
1517d57273e3ac
hexc0163edd3ac

13200111031212 has 384 divisors, whose sum is σ = 40169650913280. Its totient is φ = 3670392579840.

The previous prime is 13200111031189. The next prime is 13200111031273. The reversal of 13200111031212 is 21213011100231.

13200111031212 is a `hidden beast` number, since 1 + 320 + 0 + 11 + 10 + 312 + 12 = 666.

13200111031212 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 5190762013 + ... + 5190764555.

It is an arithmetic number, because the mean of its divisors is an integer number (104608465920).

Almost surely, 213200111031212 is an apocalyptic number.

13200111031212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13200111031212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20084825456640).

13200111031212 is an abundant number, since it is smaller than the sum of its proper divisors (26969539882068).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13200111031212 is a wasteful number, since it uses less digits than its factorization.

13200111031212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3378 (or 3370 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13200111031212 its reverse (21213011100231), we get a palindrome (34413122131443).

The spelling of 13200111031212 in words is "thirteen trillion, two hundred billion, one hundred eleven million, thirty-one thousand, two hundred twelve".