Base | Representation |
---|---|
bin | 111101011101111100… |
… | …0010111011010000011 |
3 | 110121201101102101200201 |
4 | 1322323320113122003 |
5 | 4130314242243321 |
6 | 140350202230031 |
7 | 12352053061612 |
oct | 1727370273203 |
9 | 417641371621 |
10 | 132001134211 |
11 | 50a88220961 |
12 | 216baab5317 |
13 | c5a865820b |
14 | 656317b879 |
15 | 367889c291 |
hex | 1ebbe17683 |
132001134211 has 2 divisors, whose sum is σ = 132001134212. Its totient is φ = 132001134210.
The previous prime is 132001134203. The next prime is 132001134229. The reversal of 132001134211 is 112431100231.
It is a weak prime.
It is an emirp because it is prime and its reverse (112431100231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132001134211 - 23 = 132001134203 is a prime.
It is not a weakly prime, because it can be changed into another prime (132001134271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66000567105 + 66000567106.
It is an arithmetic number, because the mean of its divisors is an integer number (66000567106).
Almost surely, 2132001134211 is an apocalyptic number.
132001134211 is a deficient number, since it is larger than the sum of its proper divisors (1).
132001134211 is an equidigital number, since it uses as much as digits as its factorization.
132001134211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 132001134211 its reverse (112431100231), we get a palindrome (244432234442).
It can be divided in two parts, 13200 and 1134211, that added together give a palindrome (1147411).
The spelling of 132001134211 in words is "one hundred thirty-two billion, one million, one hundred thirty-four thousand, two hundred eleven".
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