1320012113333 has 4 divisors (see below), whose sum is σ = 1320104262240. Its totient is φ = 1319919964428.

The previous prime is 1320012113317. The next prime is 1320012113369. The reversal of 1320012113333 is 3333112100231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320012113333 - 2⁴ = 1320012113317 is a prime.

It is a super-3 number, since 3×1320012113333³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320012113299 and 1320012113308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320012115333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46052963 + ... + 46081616.

It is an arithmetic number, because the mean of its divisors is an integer number (330026065560).

Almost surely, 2^{1320012113333} is an apocalyptic number.

It is an amenable number.

1320012113333 is a deficient number, since it is larger than the sum of its proper divisors (92148907).

1320012113333 is an equidigital number, since it uses as much as digits as its factorization.

1320012113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92148906.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1320012113333 its reverse (3333112100231), we get a palindrome (4653124213564).

The spelling of 1320012113333 in words is "one trillion, three hundred twenty billion, twelve million, one hundred thirteen thousand, three hundred thirty-three".