Base | Representation |
---|---|
bin | 11000100101100101… |
… | …00110000111111111 |
3 | 1021001221102100200122 |
4 | 30102302212013333 |
5 | 204013214431020 |
6 | 10021501045155 |
7 | 645053316206 |
oct | 142262460777 |
9 | 37057370618 |
10 | 13200155135 |
11 | 5664163a22 |
12 | 26848567bb |
13 | 13249b17ab |
14 | 8d318c23d |
15 | 523cdc125 |
hex | 312ca61ff |
13200155135 has 4 divisors (see below), whose sum is σ = 15840186168. Its totient is φ = 10560124104.
The previous prime is 13200155119. The next prime is 13200155149. The reversal of 13200155135 is 53155100231.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53155100231 = 311 ⋅170916721.
It is a cyclic number.
It is not a de Polignac number, because 13200155135 - 24 = 13200155119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320015509 + ... + 1320015518.
It is an arithmetic number, because the mean of its divisors is an integer number (3960046542).
Almost surely, 213200155135 is an apocalyptic number.
13200155135 is a deficient number, since it is larger than the sum of its proper divisors (2640031033).
13200155135 is an equidigital number, since it uses as much as digits as its factorization.
13200155135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2640031032.
The product of its (nonzero) digits is 2250, while the sum is 26.
Adding to 13200155135 its reverse (53155100231), we get a palindrome (66355255366).
The spelling of 13200155135 in words is "thirteen billion, two hundred million, one hundred fifty-five thousand, one hundred thirty-five".
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