Base | Representation |
---|---|
bin | 10011001101010111000… |
… | …111000111101100111001 |
3 | 11200012012012211011200222 |
4 | 103031113013013230321 |
5 | 133111343202203332 |
6 | 2450223541305425 |
7 | 164240144434532 |
oct | 23152707075471 |
9 | 4605165734628 |
10 | 1320016444217 |
11 | 4698a7962a79 |
12 | 1939b2a05275 |
13 | 9762800bb83 |
14 | 47c63b11689 |
15 | 2450b33d712 |
hex | 133571c7b39 |
1320016444217 has 2 divisors, whose sum is σ = 1320016444218. Its totient is φ = 1320016444216.
The previous prime is 1320016444169. The next prime is 1320016444259. The reversal of 1320016444217 is 7124446100231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1211267531776 + 108748912441 = 1100576^2 + 329771^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320016444217 is a prime.
It is not a weakly prime, because it can be changed into another prime (1320016444277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660008222108 + 660008222109.
It is an arithmetic number, because the mean of its divisors is an integer number (660008222109).
Almost surely, 21320016444217 is an apocalyptic number.
It is an amenable number.
1320016444217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320016444217 is an equidigital number, since it uses as much as digits as its factorization.
1320016444217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 35.
The spelling of 1320016444217 in words is "one trillion, three hundred twenty billion, sixteen million, four hundred forty-four thousand, two hundred seventeen".
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