Base | Representation |
---|---|
bin | 1100000000010110100111… |
… | …1000110110101001101001 |
3 | 1201201221001101211202002121 |
4 | 3000011221320312221221 |
5 | 3212233013004342301 |
6 | 44024032045231241 |
7 | 2531453351206333 |
oct | 300055170665151 |
9 | 51657041752077 |
10 | 13200211012201 |
11 | 422a1a5a95544 |
12 | 1592357b62521 |
13 | 749a0b919085 |
14 | 338c72154453 |
15 | 17d57b3dd3a1 |
hex | c0169e36a69 |
13200211012201 has 2 divisors, whose sum is σ = 13200211012202. Its totient is φ = 13200211012200.
The previous prime is 13200211012169. The next prime is 13200211012211. The reversal of 13200211012201 is 10221011200231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12461429505625 + 738781506576 = 3530075^2 + 859524^2 .
It is a cyclic number.
It is not a de Polignac number, because 13200211012201 - 25 = 13200211012169 is a prime.
It is not a weakly prime, because it can be changed into another prime (13200211012211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600105506100 + 6600105506101.
It is an arithmetic number, because the mean of its divisors is an integer number (6600105506101).
Almost surely, 213200211012201 is an apocalyptic number.
It is an amenable number.
13200211012201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200211012201 is an equidigital number, since it uses as much as digits as its factorization.
13200211012201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 13200211012201 its reverse (10221011200231), we get a palindrome (23421222212432).
The spelling of 13200211012201 in words is "thirteen trillion, two hundred billion, two hundred eleven million, twelve thousand, two hundred one".
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