Base | Representation |
---|---|
bin | 1100000000010110101100… |
… | …0101000110011110111111 |
3 | 1201201221002210110020012102 |
4 | 3000011223011012132333 |
5 | 3212233033113444444 |
6 | 44024034041455315 |
7 | 2531454013124651 |
oct | 300055305063677 |
9 | 51657083406172 |
10 | 13200230999999 |
11 | 422a2062a768a |
12 | 15923627a153b |
13 | 749a12ac6a84 |
14 | 338c74a786d1 |
15 | 17d57d03a84e |
hex | c016b1467bf |
13200230999999 has 4 divisors (see below), whose sum is σ = 13257873930360. Its totient is φ = 13142588069640.
The previous prime is 13200230999993. The next prime is 13200231000017. The reversal of 13200230999999 is 99999903200231.
13200230999999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13200230999999 - 28 = 13200230999743 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13200230999993) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28821464837 + ... + 28821465294.
It is an arithmetic number, because the mean of its divisors is an integer number (3314468482590).
Almost surely, 213200230999999 is an apocalyptic number.
13200230999999 is a deficient number, since it is larger than the sum of its proper divisors (57642930361).
13200230999999 is an equidigital number, since it uses as much as digits as its factorization.
13200230999999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57642930360.
The product of its (nonzero) digits is 19131876, while the sum is 65.
The spelling of 13200230999999 in words is "thirteen trillion, two hundred billion, two hundred thirty million, nine hundred ninety-nine thousand, nine hundred ninety-nine".
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