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13200231000000 = 26356111937569
BaseRepresentation
bin1100000000010110101100…
…0101000110011111000000
31201201221002210110020012110
43000011223011012133000
53212233033114000000
644024034041455320
72531454013124652
oct300055305063700
951657083406173
1013200231000000
11422a2062a7690
1215923627a1540
13749a12ac6a85
14338c74a786d2
1517d57d03a850
hexc016b1467c0

13200231000000 has 1568 divisors, whose sum is σ = 51577214803200. Its totient is φ = 2944512000000.

The previous prime is 13200230999993. The next prime is 13200231000017. The reversal of 13200231000000 is 13200231.

It is a happy number.

It is a super-2 number, since 2×132002310000002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 13200231000000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 223 ways as a sum of consecutive naturals, for example, 23198999716 + ... + 23199000284.

Almost surely, 213200231000000 is an apocalyptic number.

13200231000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13200231000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25788607401600).

13200231000000 is an abundant number, since it is smaller than the sum of its proper divisors (38376983803200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13200231000000 is an equidigital number, since it uses as much as digits as its factorization.

13200231000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 681 (or 646 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 13200231000000 its reverse (13200231), we get a palindrome (13200244200231).

13200231000000 divided by its reverse (13200231) gives a 6-th power (1000000 = 106).

The spelling of 13200231000000 in words is "thirteen trillion, two hundred billion, two hundred thirty-one million", and thus it is an aban number.