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132003100301020 = 2251341839115112823
BaseRepresentation
bin11110000000111001011101…
…111001110001011011011100
3122022101101002000121202012121
4132000321131321301123130
5114300214322134113040
61144425215341112324
736542623611300154
oct3600713571613334
9568341060552177
10132003100301020
1139073222896063
121297b1032586a4
135886aba21b5b0
142484dac6c3764
15103da8482dc4a
hex780e5de716dc

132003100301020 has 192 divisors, whose sum is σ = 306465711390720. Its totient is φ = 47449195776000.

The previous prime is 132003100301011. The next prime is 132003100301021. The reversal of 132003100301020 is 20103001300231.

132003100301020 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1320031003010202 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132003100300985 and 132003100301003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132003100301021) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 10294238329 + ... + 10294251151.

It is an arithmetic number, because the mean of its divisors is an integer number (1596175580160).

Almost surely, 2132003100301020 is an apocalyptic number.

132003100301020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132003100301020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (153232855695360).

132003100301020 is an abundant number, since it is smaller than the sum of its proper divisors (174462611089700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132003100301020 is a wasteful number, since it uses less digits than its factorization.

132003100301020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14876 (or 14874 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 132003100301020 its reverse (20103001300231), we get a palindrome (152106101601251).

The spelling of 132003100301020 in words is "one hundred thirty-two trillion, three billion, one hundred million, three hundred one thousand, twenty".