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132003130000 = 2454717110927
BaseRepresentation
bin111101011101111111…
…1111110101010010000
3110121201112011210101211
41322323333332222100
54130320300130000
6140350313105504
712352106043340
oct1727377765220
9417645153354
10132003130000
1150a89364375
12216bb6b8294
13c5a8ba6761
14656353ad20
153678b437ba
hex1ebbffea90

132003130000 has 200 divisors, whose sum is σ = 386737604352. Its totient is φ = 42595584000.

The previous prime is 132003129991. The next prime is 132003130013. The reversal of 132003130000 is 31300231.

It is a tau number, because it is divible by the number of its divisors (200).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1134537 + ... + 1245463.

Almost surely, 2132003130000 is an apocalyptic number.

132003130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132003130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193368802176).

132003130000 is an abundant number, since it is smaller than the sum of its proper divisors (254734474352).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132003130000 is a wasteful number, since it uses less digits than its factorization.

132003130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110979 (or 110958 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 132003130000 its reverse (31300231), we get a palindrome (132034430231).

The spelling of 132003130000 in words is "one hundred thirty-two billion, three million, one hundred thirty thousand".