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13200426438 = 232200071073
BaseRepresentation
bin11000100101100111…
…01000010111000110
31021001221221010211220
430102303220113012
5204013302121223
610021510541210
7645055526163
oct142263502706
937057833756
1013200426438
115664329841
122684967806
131324a78124
148d321d06a
15523d426e3
hex312ce85c6

13200426438 has 8 divisors (see below), whose sum is σ = 26400852888. Its totient is φ = 4400142144.

The previous prime is 13200426433. The next prime is 13200426467. The reversal of 13200426438 is 83462400231.

It is a sphenic number, since it is the product of 3 distinct primes.

13200426438 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 13200426399 and 13200426408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13200426433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100035531 + ... + 1100035542.

It is an arithmetic number, because the mean of its divisors is an integer number (3300106611).

Almost surely, 213200426438 is an apocalyptic number.

13200426438 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13200426438 is a wasteful number, since it uses less digits than its factorization.

13200426438 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2200071078.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 13200426438 its reverse (83462400231), we get a palindrome (96662826669).

The spelling of 13200426438 in words is "thirteen billion, two hundred million, four hundred twenty-six thousand, four hundred thirty-eight".

Divisors: 1 2 3 6 2200071073 4400142146 6600213219 13200426438