Base | Representation |
---|---|
bin | 10011001101011000110… |
… | …000010010001100110111 |
3 | 11200012021010200210001200 |
4 | 103031120300102030313 |
5 | 133111422231343333 |
6 | 2450230404223543 |
7 | 164240630654220 |
oct | 23153060221467 |
9 | 4605233623050 |
10 | 1320044012343 |
11 | 469911482351 |
12 | 193a0009abb3 |
13 | 97630941c84 |
14 | 47c6764a247 |
15 | 2450d986c13 |
hex | 13358c12337 |
1320044012343 has 48 divisors (see below), whose sum is σ = 2234133475392. Its totient is φ = 735298560000.
The previous prime is 1320044012333. The next prime is 1320044012401. The reversal of 1320044012343 is 3432104400231.
1320044012343 is a `hidden beast` number, since 1 + 3 + 20 + 0 + 4 + 401 + 234 + 3 = 666.
It is not a de Polignac number, because 1320044012343 - 29 = 1320044011831 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320044012333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2889423 + ... + 3314943.
It is an arithmetic number, because the mean of its divisors is an integer number (46544447404).
Almost surely, 21320044012343 is an apocalyptic number.
1320044012343 is a deficient number, since it is larger than the sum of its proper divisors (914089463049).
1320044012343 is a wasteful number, since it uses less digits than its factorization.
1320044012343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 426776 (or 426773 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 1320044012343 its reverse (3432104400231), we get a palindrome (4752148412574).
The spelling of 1320044012343 in words is "one trillion, three hundred twenty billion, forty-four million, twelve thousand, three hundred forty-three".
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