Base | Representation |
---|---|
bin | 11000100101100111… |
… | …01011101111010001 |
3 | 1021001221221211211022 |
4 | 30102303223233101 |
5 | 204013303042043 |
6 | 10021511125225 |
7 | 645055614416 |
oct | 142263535721 |
9 | 37057854738 |
10 | 13200440273 |
11 | 5664339179 |
12 | 2684973815 |
13 | 1324a81507 |
14 | 8d322410d |
15 | 523d46868 |
hex | 312cebbd1 |
13200440273 has 2 divisors, whose sum is σ = 13200440274. Its totient is φ = 13200440272.
The previous prime is 13200440179. The next prime is 13200440293. The reversal of 13200440273 is 37204400231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12729029329 + 471410944 = 112823^2 + 21712^2 .
It is a cyclic number.
It is not a de Polignac number, because 13200440273 - 220 = 13199391697 is a prime.
It is not a weakly prime, because it can be changed into another prime (13200440293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600220136 + 6600220137.
It is an arithmetic number, because the mean of its divisors is an integer number (6600220137).
Almost surely, 213200440273 is an apocalyptic number.
It is an amenable number.
13200440273 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200440273 is an equidigital number, since it uses as much as digits as its factorization.
13200440273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 26.
The spelling of 13200440273 in words is "thirteen billion, two hundred million, four hundred forty thousand, two hundred seventy-three".
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