1320044032231 has 4 divisors (see below), whose sum is σ = 1320179445000. Its totient is φ = 1319908619464.

The previous prime is 1320044032183. The next prime is 1320044032247. The reversal of 1320044032231 is 1322304400231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1320044032231 - 2¹⁹ = 1320043507943 is a prime.

It is a super-2 number, since 2×1320044032231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320044032196 and 1320044032205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320044032271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67691761 + ... + 67711258.

It is an arithmetic number, because the mean of its divisors is an integer number (330044861250).

Almost surely, 2^{1320044032231} is an apocalyptic number.

1320044032231 is a deficient number, since it is larger than the sum of its proper divisors (135412769).

1320044032231 is an equidigital number, since it uses as much as digits as its factorization.

1320044032231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135412768.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 1320044032231 its reverse (1322304400231), we get a palindrome (2642348432462).

The spelling of 1320044032231 in words is "one trillion, three hundred twenty billion, forty-four million, thirty-two thousand, two hundred thirty-one".