Base | Representation |
---|---|
bin | 1100000000010111100111… |
… | …1110110011100101111111 |
3 | 1201201221202012212221200222 |
4 | 3000011321332303211333 |
5 | 3212234041114223444 |
6 | 44024114532211555 |
7 | 2531463140142155 |
oct | 300057176634577 |
9 | 51657665787628 |
10 | 13200481007999 |
11 | 422a32443636a |
12 | 1592412469bbb |
13 | 749a5283ccbc |
14 | 338c99d573d5 |
15 | 17d594e71eee |
hex | c0179fb397f |
13200481007999 has 4 divisors (see below), whose sum is σ = 13397503112664. Its totient is φ = 13003458903336.
The previous prime is 13200481007993. The next prime is 13200481008107. The reversal of 13200481007999 is 99970018400231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13200481007999 - 240 = 12100969380223 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13200481007999.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13200481007993) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98511052232 + ... + 98511052365.
It is an arithmetic number, because the mean of its divisors is an integer number (3349375778166).
Almost surely, 213200481007999 is an apocalyptic number.
13200481007999 is a deficient number, since it is larger than the sum of its proper divisors (197022104665).
13200481007999 is an equidigital number, since it uses as much as digits as its factorization.
13200481007999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197022104664.
The product of its (nonzero) digits is 979776, while the sum is 53.
The spelling of 13200481007999 in words is "thirteen trillion, two hundred billion, four hundred eighty-one million, seven thousand, nine hundred ninety-nine".
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