Base | Representation |
---|---|
bin | 11110000000111101101000… |
… | …101000001101010101110011 |
3 | 122022101210121212221212000011 |
4 | 132000331220220031111303 |
5 | 114300303003223312202 |
6 | 1144431235354035351 |
7 | 36543142526362054 |
oct | 3600755050152563 |
9 | 568353555855004 |
10 | 132007575213427 |
11 | 39075109860a81 |
12 | 1297bb51a18b57 |
13 | 5887351350064 |
14 | 24852b4b3c72b |
15 | 103dc47613bd7 |
hex | 780f68a0d573 |
132007575213427 has 2 divisors, whose sum is σ = 132007575213428. Its totient is φ = 132007575213426.
The previous prime is 132007575213383. The next prime is 132007575213467. The reversal of 132007575213427 is 724312575700231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132007575213427 is a prime.
It is not a weakly prime, because it can be changed into another prime (132007575213467) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66003787606713 + 66003787606714.
It is an arithmetic number, because the mean of its divisors is an integer number (66003787606714).
Almost surely, 2132007575213427 is an apocalyptic number.
132007575213427 is a deficient number, since it is larger than the sum of its proper divisors (1).
132007575213427 is an equidigital number, since it uses as much as digits as its factorization.
132007575213427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2469600, while the sum is 49.
The spelling of 132007575213427 in words is "one hundred thirty-two trillion, seven billion, five hundred seventy-five million, two hundred thirteen thousand, four hundred twenty-seven".
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