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13201020113 is a prime number
BaseRepresentation
bin11000100101101011…
…11001010011010001
31021002000001022012212
430102311321103101
5204013430120423
610021531401505
7645063551051
oct142265712321
937060038185
1013201020113
1156646a4886
122684bb3295
131324c25408
148d3335561
15523e0d578
hex312d794d1

13201020113 has 2 divisors, whose sum is σ = 13201020114. Its totient is φ = 13201020112.

The previous prime is 13201020101. The next prime is 13201020137. The reversal of 13201020113 is 31102010231.

13201020113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11248087249 + 1952932864 = 106057^2 + 44192^2 .

It is a cyclic number.

It is not a de Polignac number, because 13201020113 - 214 = 13201003729 is a prime.

It is not a weakly prime, because it can be changed into another prime (13201020163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600510056 + 6600510057.

It is an arithmetic number, because the mean of its divisors is an integer number (6600510057).

Almost surely, 213201020113 is an apocalyptic number.

It is an amenable number.

13201020113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201020113 is an equidigital number, since it uses as much as digits as its factorization.

13201020113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13201020113 its reverse (31102010231), we get a palindrome (44303030344).

The spelling of 13201020113 in words is "thirteen billion, two hundred one million, twenty thousand, one hundred thirteen".