Base | Representation |
---|---|
bin | 111101011110001111… |
… | …0000111101100100011 |
3 | 110121202002001012222201 |
4 | 1322330132013230203 |
5 | 4130324311000311 |
6 | 140351154314031 |
7 | 12352233152314 |
oct | 1727436075443 |
9 | 417662035881 |
10 | 132011031331 |
11 | 50a928707a3 |
12 | 21702288917 |
13 | c5aa711cba |
14 | 65645d660b |
15 | 36796a49c1 |
hex | 1ebc787b23 |
132011031331 has 2 divisors, whose sum is σ = 132011031332. Its totient is φ = 132011031330.
The previous prime is 132011031319. The next prime is 132011031443. The reversal of 132011031331 is 133130110231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132011031331 - 27 = 132011031203 is a prime.
It is a super-2 number, since 2×1320110313312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132011031299 and 132011031308.
It is not a weakly prime, because it can be changed into another prime (132011031301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66005515665 + 66005515666.
It is an arithmetic number, because the mean of its divisors is an integer number (66005515666).
Almost surely, 2132011031331 is an apocalyptic number.
132011031331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132011031331 is an equidigital number, since it uses as much as digits as its factorization.
132011031331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 132011031331 its reverse (133130110231), we get a palindrome (265141141562).
The spelling of 132011031331 in words is "one hundred thirty-two billion, eleven million, thirty-one thousand, three hundred thirty-one".
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