132011212112021 has 4 divisors (see below), whose sum is σ = 144012231394944. Its totient is φ = 120010192829100.

The previous prime is 132011212111981. The next prime is 132011212112033. The reversal of 132011212112021 is 120211212110231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132011212112021 - 2³⁴ = 131994032242837 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132011212111984 and 132011212112002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132011212112041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6000509641445 + ... + 6000509641466.

It is an arithmetic number, because the mean of its divisors is an integer number (36003057848736).

Almost surely, 2^{132011212112021} is an apocalyptic number.

132011212112021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

132011212112021 is a deficient number, since it is larger than the sum of its proper divisors (12001019282923).

132011212112021 is a wasteful number, since it uses less digits than its factorization.

132011212112021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12001019282922.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 132011212112021 its reverse (120211212110231), we get a palindrome (252222424222252).

The spelling of 132011212112021 in words is "one hundred thirty-two trillion, eleven billion, two hundred twelve million, one hundred twelve thousand, twenty-one".