Base | Representation |
---|---|
bin | 1100000000011010000000… |
… | …1001010101011100011111 |
3 | 1201202000101211201021100211 |
4 | 3000012200021111130133 |
5 | 3212241344023133203 |
6 | 44024302244033251 |
7 | 2531515043433334 |
oct | 300064011253437 |
9 | 51660354637324 |
10 | 13201121302303 |
11 | 422a622905a10 |
12 | 1592570992827 |
13 | 749b253a637c |
14 | 338d1adcc98b |
15 | 17d5d129dc6d |
hex | c01a025571f |
13201121302303 has 4 divisors (see below), whose sum is σ = 14401223238888. Its totient is φ = 12001019365720.
The previous prime is 13201121302289. The next prime is 13201121302321. The reversal of 13201121302303 is 30320312110231.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-13201121302303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13201121302333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600050968276 + ... + 600050968297.
It is an arithmetic number, because the mean of its divisors is an integer number (3600305809722).
Almost surely, 213201121302303 is an apocalyptic number.
13201121302303 is a deficient number, since it is larger than the sum of its proper divisors (1200101936585).
13201121302303 is a wasteful number, since it uses less digits than its factorization.
13201121302303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1200101936584.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13201121302303 its reverse (30320312110231), we get a palindrome (43521433412534).
The spelling of 13201121302303 in words is "thirteen trillion, two hundred one billion, one hundred twenty-one million, three hundred two thousand, three hundred three".
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