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13201121302333 is a prime number
BaseRepresentation
bin1100000000011010000000…
…1001010101011100111101
31201202000101211201021101221
43000012200021111130331
53212241344023133313
644024302244033341
72531515043433406
oct300064011253475
951660354637357
1013201121302333
11422a622905a38
121592570992851
13749b253a63a3
14338d1adcc9ad
1517d5d129dc8d
hexc01a025573d

13201121302333 has 2 divisors, whose sum is σ = 13201121302334. Its totient is φ = 13201121302332.

The previous prime is 13201121302321. The next prime is 13201121302337. The reversal of 13201121302333 is 33320312110231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11264467762564 + 1936653539769 = 3356258^2 + 1391637^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13201121302333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13201121302298 and 13201121302307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13201121302337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600560651166 + 6600560651167.

It is an arithmetic number, because the mean of its divisors is an integer number (6600560651167).

Almost surely, 213201121302333 is an apocalyptic number.

It is an amenable number.

13201121302333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201121302333 is an equidigital number, since it uses as much as digits as its factorization.

13201121302333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13201121302333 its reverse (33320312110231), we get a palindrome (46521433412564).

The spelling of 13201121302333 in words is "thirteen trillion, two hundred one billion, one hundred twenty-one million, three hundred two thousand, three hundred thirty-three".