Base | Representation |
---|---|
bin | 1100000000011010000010… |
… | …1010100001111101001110 |
3 | 1201202000102110002101021002 |
4 | 3000012200222201331032 |
5 | 3212241403240114202 |
6 | 44024303154340302 |
7 | 2531515210415522 |
oct | 300064052417516 |
9 | 51660373071232 |
10 | 13201130004302 |
11 | 422a627809949 |
12 | 159257388a692 |
13 | 749b27132196 |
14 | 338d1c215d82 |
15 | 17d5d1e1c302 |
hex | c01a0aa1f4e |
13201130004302 has 4 divisors (see below), whose sum is σ = 19801695006456. Its totient is φ = 6600565002150.
The previous prime is 13201130004289. The next prime is 13201130004331. The reversal of 13201130004302 is 20340003110231.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3300282501074 + ... + 3300282501077.
It is an arithmetic number, because the mean of its divisors is an integer number (4950423751614).
Almost surely, 213201130004302 is an apocalyptic number.
13201130004302 is a deficient number, since it is larger than the sum of its proper divisors (6600565002154).
13201130004302 is an equidigital number, since it uses as much as digits as its factorization.
13201130004302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6600565002153.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13201130004302 its reverse (20340003110231), we get a palindrome (33541133114533).
The spelling of 13201130004302 in words is "thirteen trillion, two hundred one billion, one hundred thirty million, four thousand, three hundred two".
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