Base | Representation |
---|---|
bin | 10011001101011100110… |
… | …111111100101100001011 |
3 | 11200012102221202100000012 |
4 | 103031130313330230023 |
5 | 133112042430132001 |
6 | 2450241313502135 |
7 | 164242430315156 |
oct | 23153467745413 |
9 | 4605387670005 |
10 | 1320113130251 |
11 | 4699474a0693 |
12 | 193a1b27194b |
13 | 97642062146 |
14 | 47c728bcc9d |
15 | 24514a8b2bb |
hex | 1335cdfcb0b |
1320113130251 has 2 divisors, whose sum is σ = 1320113130252. Its totient is φ = 1320113130250.
The previous prime is 1320113130239. The next prime is 1320113130313. The reversal of 1320113130251 is 1520313110231.
It is a weak prime.
It is an emirp because it is prime and its reverse (1520313110231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1320113130251 - 26 = 1320113130187 is a prime.
It is a super-2 number, since 2×13201131302512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1320113130851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660056565125 + 660056565126.
It is an arithmetic number, because the mean of its divisors is an integer number (660056565126).
Almost surely, 21320113130251 is an apocalyptic number.
1320113130251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320113130251 is an equidigital number, since it uses as much as digits as its factorization.
1320113130251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 1320113130251 its reverse (1520313110231), we get a palindrome (2840426240482).
The spelling of 1320113130251 in words is "one trillion, three hundred twenty billion, one hundred thirteen million, one hundred thirty thousand, two hundred fifty-one".
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