Base | Representation |
---|---|
bin | 11000100101101100… |
… | …11111110101010011 |
3 | 1021002000100022201021 |
4 | 30102312133311103 |
5 | 204014000143224 |
6 | 10021535020311 |
7 | 645065106145 |
oct | 142266376523 |
9 | 37060308637 |
10 | 13201177939 |
11 | 56647a2414 |
12 | 268506a697 |
13 | 1324c7c1c1 |
14 | 8d3376c95 |
15 | 523e401e4 |
hex | 312d9fd53 |
13201177939 has 2 divisors, whose sum is σ = 13201177940. Its totient is φ = 13201177938.
The previous prime is 13201177921. The next prime is 13201177967. The reversal of 13201177939 is 93977110231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13201177939 - 215 = 13201145171 is a prime.
It is a super-3 number, since 3×132011779393 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13201177895 and 13201177904.
It is not a weakly prime, because it can be changed into another prime (13201177439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600588969 + 6600588970.
It is an arithmetic number, because the mean of its divisors is an integer number (6600588970).
Almost surely, 213201177939 is an apocalyptic number.
13201177939 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201177939 is an equidigital number, since it uses as much as digits as its factorization.
13201177939 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 71442, while the sum is 43.
The spelling of 13201177939 in words is "thirteen billion, two hundred one million, one hundred seventy-seven thousand, nine hundred thirty-nine".
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