Base | Representation |
---|---|
bin | 10011001101011101011… |
… | …001111010001111001110 |
3 | 11200012110120111122102102 |
4 | 103031131121322033032 |
5 | 133112102220024402 |
6 | 2450242232355102 |
7 | 164242566065045 |
oct | 23153531721716 |
9 | 4605416448372 |
10 | 1320122033102 |
11 | 469951521514 |
12 | 193a22245a92 |
13 | 97643b5b4c2 |
14 | 47c73b5955c |
15 | 24515749102 |
hex | 1335d67a3ce |
1320122033102 has 4 divisors (see below), whose sum is σ = 1980183049656. Its totient is φ = 660061016550.
The previous prime is 1320122033099. The next prime is 1320122033123. The reversal of 1320122033102 is 2013302210231.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330030508274 + ... + 330030508277.
It is an arithmetic number, because the mean of its divisors is an integer number (495045762414).
Almost surely, 21320122033102 is an apocalyptic number.
1320122033102 is a deficient number, since it is larger than the sum of its proper divisors (660061016554).
1320122033102 is an equidigital number, since it uses as much as digits as its factorization.
1320122033102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 660061016553.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1320122033102 its reverse (2013302210231), we get a palindrome (3333424243333).
The spelling of 1320122033102 in words is "one trillion, three hundred twenty billion, one hundred twenty-two million, thirty-three thousand, one hundred two".
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