Base | Representation |
---|---|
bin | 1100000000011010011000… |
… | …1110000111101111101011 |
3 | 1201202000122221111020102212 |
4 | 3000012212032013233223 |
5 | 3212242101121021303 |
6 | 44024320324315335 |
7 | 2531520421634144 |
oct | 300064616075753 |
9 | 51660587436385 |
10 | 13201223220203 |
11 | 422a675397387 |
12 | 159259ab42b4b |
13 | 749b4053bb15 |
14 | 338d2a75cacb |
15 | 17d5da1d1ad8 |
hex | c01a6387beb |
13201223220203 has 2 divisors, whose sum is σ = 13201223220204. Its totient is φ = 13201223220202.
The previous prime is 13201223220187. The next prime is 13201223220257. The reversal of 13201223220203 is 30202232210231.
13201223220203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13201223220203 - 24 = 13201223220187 is a prime.
It is a super-2 number, since 2×132012232202032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13201223220503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600611610101 + 6600611610102.
It is an arithmetic number, because the mean of its divisors is an integer number (6600611610102).
Almost surely, 213201223220203 is an apocalyptic number.
13201223220203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201223220203 is an equidigital number, since it uses as much as digits as its factorization.
13201223220203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13201223220203 its reverse (30202232210231), we get a palindrome (43403455430434).
The spelling of 13201223220203 in words is "thirteen trillion, two hundred one billion, two hundred twenty-three million, two hundred twenty thousand, two hundred three".
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