Base | Representation |
---|---|
bin | 10011001101011110000… |
… | …100100111111000101001 |
3 | 11200012111100120111211211 |
4 | 103031132010213320221 |
5 | 133112113101330441 |
6 | 2450243312353121 |
7 | 164243063211316 |
oct | 23153604477051 |
9 | 4605440514754 |
10 | 1320133230121 |
11 | 469957879a52 |
12 | 193a25b457a1 |
13 | 9764627bb64 |
14 | 47c75431d0d |
15 | 2451670ba81 |
hex | 1335e127e29 |
1320133230121 has 2 divisors, whose sum is σ = 1320133230122. Its totient is φ = 1320133230120.
The previous prime is 1320133230107. The next prime is 1320133230127. The reversal of 1320133230121 is 1210323310231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1260704541721 + 59428688400 = 1122811^2 + 243780^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320133230121 - 223 = 1320124841513 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1320133230092 and 1320133230101.
It is not a weakly prime, because it can be changed into another prime (1320133230127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660066615060 + 660066615061.
It is an arithmetic number, because the mean of its divisors is an integer number (660066615061).
Almost surely, 21320133230121 is an apocalyptic number.
It is an amenable number.
1320133230121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320133230121 is an equidigital number, since it uses as much as digits as its factorization.
1320133230121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1320133230121 its reverse (1210323310231), we get a palindrome (2530456540352).
The spelling of 1320133230121 in words is "one trillion, three hundred twenty billion, one hundred thirty-three million, two hundred thirty thousand, one hundred twenty-one".
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