Base | Representation |
---|---|
bin | 1100000000011010110100… |
… | …1100000100011110001111 |
3 | 1201202000222002110111221221 |
4 | 3000012231030010132033 |
5 | 3212242321032414043 |
6 | 44024340102104211 |
7 | 2531523341405533 |
oct | 300065514043617 |
9 | 51660862414857 |
10 | 13201340123023 |
11 | 422a725383188 |
12 | 159261211b067 |
13 | 749b5b8200a0 |
14 | 338d3c0adbc3 |
15 | 17d5e55c48ed |
hex | c01ad30478f |
13201340123023 has 4 divisors (see below), whose sum is σ = 14216827824808. Its totient is φ = 12185852421240.
The previous prime is 13201340122843. The next prime is 13201340123129. The reversal of 13201340123023 is 32032104310231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13201340123023 is a prime.
It is a super-3 number, since 3×132013401230233 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13201340103023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507743850873 + ... + 507743850898.
It is an arithmetic number, because the mean of its divisors is an integer number (3554206956202).
Almost surely, 213201340123023 is an apocalyptic number.
13201340123023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13201340123023 is a deficient number, since it is larger than the sum of its proper divisors (1015487701785).
13201340123023 is a wasteful number, since it uses less digits than its factorization.
13201340123023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1015487701784.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13201340123023 its reverse (32032104310231), we get a palindrome (45233444433254).
The spelling of 13201340123023 in words is "thirteen trillion, two hundred one billion, three hundred forty million, one hundred twenty-three thousand, twenty-three".
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