Base | Representation |
---|---|
bin | 1100000000011010111010… |
… | …0001011100011110111110 |
3 | 1201202001000122120120100201 |
4 | 3000012232201130132332 |
5 | 3212242342300103424 |
6 | 44024342221514114 |
7 | 2531524032551215 |
oct | 300065641343676 |
9 | 51661018516321 |
10 | 13201362503614 |
11 | 422a736a7a03a |
12 | 159261971293a |
13 | 749b63357c3c |
14 | 338d4105807c |
15 | 17d5e7545d44 |
hex | c01ae85c7be |
13201362503614 has 4 divisors (see below), whose sum is σ = 19802043755424. Its totient is φ = 6600681251806.
The previous prime is 13201362503611. The next prime is 13201362503621. The reversal of 13201362503614 is 41630526310231.
13201362503614 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13201362503611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3300340625902 + ... + 3300340625905.
It is an arithmetic number, because the mean of its divisors is an integer number (4950510938856).
Almost surely, 213201362503614 is an apocalyptic number.
13201362503614 is a deficient number, since it is larger than the sum of its proper divisors (6600681251810).
13201362503614 is an equidigital number, since it uses as much as digits as its factorization.
13201362503614 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6600681251809.
The product of its (nonzero) digits is 77760, while the sum is 37.
Adding to 13201362503614 its reverse (41630526310231), we get a palindrome (54831888813845).
The spelling of 13201362503614 in words is "thirteen trillion, two hundred one billion, three hundred sixty-two million, five hundred three thousand, six hundred fourteen".
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