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13201402000403 is a prime number
BaseRepresentation
bin1100000000011011000011…
…1000000111010000010011
31201202001010101220012202202
43000012300320013100103
53212242432403003103
644024350152233415
72531525022352211
oct300066070072023
951661111805682
1013201402000403
11422a7572a6611
12159262a99b86b
13749b6b5a6716
14338d463b9cb1
1517d5eac48988
hexc01b0e07413

13201402000403 has 2 divisors, whose sum is σ = 13201402000404. Its totient is φ = 13201402000402.

The previous prime is 13201402000393. The next prime is 13201402000459. The reversal of 13201402000403 is 30400020410231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13201402000403 - 24 = 13201402000387 is a prime.

It is not a weakly prime, because it can be changed into another prime (13201402000903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600701000201 + 6600701000202.

It is an arithmetic number, because the mean of its divisors is an integer number (6600701000202).

Almost surely, 213201402000403 is an apocalyptic number.

13201402000403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201402000403 is an equidigital number, since it uses as much as digits as its factorization.

13201402000403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13201402000403 its reverse (30400020410231), we get a palindrome (43601422410634).

The spelling of 13201402000403 in words is "thirteen trillion, two hundred one billion, four hundred two million, four hundred three", and thus it is an aban number.