Base | Representation |
---|---|
bin | 111101011110010100… |
… | …1100001101100111010 |
3 | 110121202021200010122021 |
4 | 1322330221201230322 |
5 | 4130331042141214 |
6 | 140351342345054 |
7 | 12352300444651 |
oct | 1727451415472 |
9 | 417667603567 |
10 | 132014021434 |
11 | 50a94523259 |
12 | 2170328b18a |
13 | c5ab21aca9 |
14 | 6564b74198 |
15 | 3679a95924 |
hex | 1ebca61b3a |
132014021434 has 4 divisors (see below), whose sum is σ = 198021032154. Its totient is φ = 66007010716.
The previous prime is 132014021431. The next prime is 132014021459. The reversal of 132014021434 is 434120410231.
132014021434 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 124669017225 + 7345004209 = 353085^2 + 85703^2 .
It is a super-2 number, since 2×1320140214342 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132014021399 and 132014021408.
It is not an unprimeable number, because it can be changed into a prime (132014021431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33003505357 + ... + 33003505360.
Almost surely, 2132014021434 is an apocalyptic number.
132014021434 is a deficient number, since it is larger than the sum of its proper divisors (66007010720).
132014021434 is an equidigital number, since it uses as much as digits as its factorization.
132014021434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66007010719.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 132014021434 its reverse (434120410231), we get a palindrome (566134431665).
The spelling of 132014021434 in words is "one hundred thirty-two billion, fourteen million, twenty-one thousand, four hundred thirty-four".
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