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132014021434 = 266007010717
BaseRepresentation
bin111101011110010100…
…1100001101100111010
3110121202021200010122021
41322330221201230322
54130331042141214
6140351342345054
712352300444651
oct1727451415472
9417667603567
10132014021434
1150a94523259
122170328b18a
13c5ab21aca9
146564b74198
153679a95924
hex1ebca61b3a

132014021434 has 4 divisors (see below), whose sum is σ = 198021032154. Its totient is φ = 66007010716.

The previous prime is 132014021431. The next prime is 132014021459. The reversal of 132014021434 is 434120410231.

132014021434 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 124669017225 + 7345004209 = 353085^2 + 85703^2 .

It is a super-2 number, since 2×1320140214342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132014021399 and 132014021408.

It is not an unprimeable number, because it can be changed into a prime (132014021431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33003505357 + ... + 33003505360.

Almost surely, 2132014021434 is an apocalyptic number.

132014021434 is a deficient number, since it is larger than the sum of its proper divisors (66007010720).

132014021434 is an equidigital number, since it uses as much as digits as its factorization.

132014021434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66007010719.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 132014021434 its reverse (434120410231), we get a palindrome (566134431665).

The spelling of 132014021434 in words is "one hundred thirty-two billion, fourteen million, twenty-one thousand, four hundred thirty-four".

Divisors: 1 2 66007010717 132014021434