Base | Representation |
---|---|
bin | 10011001101011110100… |
… | …010110000111010001100 |
3 | 11200012111220102221100221 |
4 | 103031132202300322030 |
5 | 133112122112201104 |
6 | 2450244154001124 |
7 | 164243220320164 |
oct | 23153642607214 |
9 | 4605456387327 |
10 | 1320141131404 |
11 | 469961286337 |
12 | 193a287161a4 |
13 | 97647ab7384 |
14 | 47c764cb5a4 |
15 | 2451726cc54 |
hex | 1335e8b0e8c |
1320141131404 has 6 divisors (see below), whose sum is σ = 2310246979964. Its totient is φ = 660070565700.
The previous prime is 1320141131359. The next prime is 1320141131411. The reversal of 1320141131404 is 4041311410231.
It is a super-2 number, since 2×13201411314042 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165017641422 + ... + 165017641429.
Almost surely, 21320141131404 is an apocalyptic number.
It is an amenable number.
1320141131404 is a deficient number, since it is larger than the sum of its proper divisors (990105848560).
1320141131404 is a wasteful number, since it uses less digits than its factorization.
1320141131404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 330035282855 (or 330035282853 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1320141131404 its reverse (4041311410231), we get a palindrome (5361452541635).
The spelling of 1320141131404 in words is "one trillion, three hundred twenty billion, one hundred forty-one million, one hundred thirty-one thousand, four hundred four".
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