13201430502041 has 4 divisors (see below), whose sum is σ = 13204396453584. Its totient is φ = 13198464550500.

The previous prime is 13201430502011. The next prime is 13201430502059. The reversal of 13201430502041 is 14020503410231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13201430502041 - 2³⁸ = 12926552595097 is a prime.

It is a super-3 number, since 3×13201430502041³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13201430502041.

It is not an unprimeable number, because it can be changed into a prime (13201430502011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1482969095 + ... + 1482977996.

It is an arithmetic number, because the mean of its divisors is an integer number (3301099113396).

Almost surely, 2^{13201430502041} is an apocalyptic number.

It is an amenable number.

13201430502041 is a deficient number, since it is larger than the sum of its proper divisors (2965951543).

13201430502041 is an equidigital number, since it uses as much as digits as its factorization.

13201430502041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2965951542.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 13201430502041 its reverse (14020503410231), we get a palindrome (27221933912272).

The spelling of 13201430502041 in words is "thirteen trillion, two hundred one billion, four hundred thirty million, five hundred two thousand, forty-one".