Base | Representation |
---|---|
bin | 1100000000011011001010… |
… | …0100110101101010101011 |
3 | 1201202001012101112020200122 |
4 | 3000012302210311222223 |
5 | 3212243012202031214 |
6 | 44024353051153455 |
7 | 2531525516540342 |
oct | 300066244655253 |
9 | 51661171466618 |
10 | 13201430502059 |
11 | 422a7713a32a8 |
12 | 159263844588b |
13 | 749b744756c7 |
14 | 338d4a0b8b59 |
15 | 17d5ed4c888e |
hex | c01b2935aab |
13201430502059 has 2 divisors, whose sum is σ = 13201430502060. Its totient is φ = 13201430502058.
The previous prime is 13201430502011. The next prime is 13201430502103. The reversal of 13201430502059 is 95020503410231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13201430502059 - 236 = 13132711025323 is a prime.
It is not a weakly prime, because it can be changed into another prime (13201430552059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600715251029 + 6600715251030.
It is an arithmetic number, because the mean of its divisors is an integer number (6600715251030).
Almost surely, 213201430502059 is an apocalyptic number.
13201430502059 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201430502059 is an equidigital number, since it uses as much as digits as its factorization.
13201430502059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 13201430502059 in words is "thirteen trillion, two hundred one billion, four hundred thirty million, five hundred two thousand, fifty-nine".
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