Base | Representation |
---|---|
bin | 1100000000011011011110… |
… | …0001001111011011110111 |
3 | 1201202001102011121012011112 |
4 | 3000012313201033123313 |
5 | 3212243144420220421 |
6 | 44024405213025235 |
7 | 2531530544541665 |
oct | 300066741173367 |
9 | 51661364535145 |
10 | 13201513445111 |
11 | 422a8041a4682 |
12 | 159266018521b |
13 | 749b886c6534 |
14 | 338d57109c35 |
15 | 17d60590e45b |
hex | c01b784f6f7 |
13201513445111 has 4 divisors (see below), whose sum is σ = 13201674495672. Its totient is φ = 13201352394552.
The previous prime is 13201513445093. The next prime is 13201513445149. The reversal of 13201513445111 is 11154431510231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13201513445111 - 242 = 8803466934007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13201510445111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80402261 + ... + 80566286.
It is an arithmetic number, because the mean of its divisors is an integer number (3300418623918).
Almost surely, 213201513445111 is an apocalyptic number.
13201513445111 is a deficient number, since it is larger than the sum of its proper divisors (161050561).
13201513445111 is an equidigital number, since it uses as much as digits as its factorization.
13201513445111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161050560.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 13201513445111 its reverse (11154431510231), we get a palindrome (24355944955342).
The spelling of 13201513445111 in words is "thirteen trillion, two hundred one billion, five hundred thirteen million, four hundred forty-five thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •