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13201513445111 = 82013160968547
BaseRepresentation
bin1100000000011011011110…
…0001001111011011110111
31201202001102011121012011112
43000012313201033123313
53212243144420220421
644024405213025235
72531530544541665
oct300066741173367
951661364535145
1013201513445111
11422a8041a4682
12159266018521b
13749b886c6534
14338d57109c35
1517d60590e45b
hexc01b784f6f7

13201513445111 has 4 divisors (see below), whose sum is σ = 13201674495672. Its totient is φ = 13201352394552.

The previous prime is 13201513445093. The next prime is 13201513445149. The reversal of 13201513445111 is 11154431510231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13201513445111 - 242 = 8803466934007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13201510445111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80402261 + ... + 80566286.

It is an arithmetic number, because the mean of its divisors is an integer number (3300418623918).

Almost surely, 213201513445111 is an apocalyptic number.

13201513445111 is a deficient number, since it is larger than the sum of its proper divisors (161050561).

13201513445111 is an equidigital number, since it uses as much as digits as its factorization.

13201513445111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161050560.

The product of its (nonzero) digits is 7200, while the sum is 32.

Adding to 13201513445111 its reverse (11154431510231), we get a palindrome (24355944955342).

The spelling of 13201513445111 in words is "thirteen trillion, two hundred one billion, five hundred thirteen million, four hundred forty-five thousand, one hundred eleven".

Divisors: 1 82013 160968547 13201513445111