Base | Representation |
---|---|
bin | 11110000001000101000011… |
… | …000010001010100100101011 |
3 | 122022102120011120121100101211 |
4 | 132001011003002022210223 |
5 | 114300420303302340334 |
6 | 1144435033235253551 |
7 | 36543544003452544 |
oct | 3601050302124453 |
9 | 568376146540354 |
10 | 132015534418219 |
11 | 390785235a5381 |
12 | 129815b344a2b7 |
13 | 588801c2ab6aa |
14 | 248582bc274cb |
15 | 103e061251a64 |
hex | 78114308a92b |
132015534418219 has 2 divisors, whose sum is σ = 132015534418220. Its totient is φ = 132015534418218.
The previous prime is 132015534418199. The next prime is 132015534418231. The reversal of 132015534418219 is 912814435510231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132015534418219 - 219 = 132015533893931 is a prime.
It is a super-2 number, since 2×1320155344182192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132015534118219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007767209109 + 66007767209110.
It is an arithmetic number, because the mean of its divisors is an integer number (66007767209110).
Almost surely, 2132015534418219 is an apocalyptic number.
132015534418219 is a deficient number, since it is larger than the sum of its proper divisors (1).
132015534418219 is an equidigital number, since it uses as much as digits as its factorization.
132015534418219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1036800, while the sum is 49.
The spelling of 132015534418219 in words is "one hundred thirty-two trillion, fifteen billion, five hundred thirty-four million, four hundred eighteen thousand, two hundred nineteen".
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