Base | Representation |
---|---|
bin | 11000100101110011… |
… | …01001100101101011 |
3 | 1021002001220022022101 |
4 | 30102321221211223 |
5 | 204014203114311 |
6 | 10022004434231 |
7 | 645105120355 |
oct | 142271514553 |
9 | 37061808271 |
10 | 13202004331 |
11 | 566520728a |
12 | 26853a8977 |
13 | 13251ab3a9 |
14 | 8d35100d5 |
15 | 524054ec1 |
hex | 312e6996b |
13202004331 has 2 divisors, whose sum is σ = 13202004332. Its totient is φ = 13202004330.
The previous prime is 13202004287. The next prime is 13202004349. The reversal of 13202004331 is 13340020231.
It is a strong prime.
It is an emirp because it is prime and its reverse (13340020231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13202004331 - 217 = 13201873259 is a prime.
It is a super-2 number, since 2×132020043312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13202004299 and 13202004308.
It is not a weakly prime, because it can be changed into another prime (13202004371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601002165 + 6601002166.
It is an arithmetic number, because the mean of its divisors is an integer number (6601002166).
Almost surely, 213202004331 is an apocalyptic number.
13202004331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13202004331 is an equidigital number, since it uses as much as digits as its factorization.
13202004331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13202004331 its reverse (13340020231), we get a palindrome (26542024562).
The spelling of 13202004331 in words is "thirteen billion, two hundred two million, four thousand, three hundred thirty-one".
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