Base | Representation |
---|---|
bin | 1100000000011101010111… |
… | …0010100110001011100000 |
3 | 1201202002201120020110110200 |
4 | 3000013111302212023200 |
5 | 3212300214423424300 |
6 | 44024531434225200 |
7 | 2531546252410101 |
oct | 300072562461340 |
9 | 51662646213420 |
10 | 13202021311200 |
11 | 422aa44943a17 |
12 | 1592782285200 |
13 | 749c399a3b07 |
14 | 338da474c3a8 |
15 | 17d6352cd200 |
hex | c01d5ca62e0 |
13202021311200 has 216 divisors, whose sum is σ = 48055358385216. Its totient is φ = 3406973184000.
The previous prime is 13202021311093. The next prime is 13202021311207. The reversal of 13202021311200 is 211312020231.
13202021311200 is a `hidden beast` number, since 1 + 320 + 20 + 213 + 112 + 0 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13202021311207) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 29351221 + ... + 29797620.
Almost surely, 213202021311200 is an apocalyptic number.
13202021311200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13202021311200 is an abundant number, since it is smaller than the sum of its proper divisors (34853337074016).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13202021311200 is a wasteful number, since it uses less digits than its factorization.
13202021311200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59148898 (or 59148882 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 13202021311200 its reverse (211312020231), we get a palindrome (13413333331431).
The spelling of 13202021311200 in words is "thirteen trillion, two hundred two billion, twenty-one million, three hundred eleven thousand, two hundred".
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