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1320203123132 = 221279258053777
BaseRepresentation
bin10011001101100010001…
…111001111100110111100
311200012200020002110000212
4103031202033033212330
5133112233444420012
62450254250411552
7164244602251115
oct23154217174674
94605606073025
101320203123132
11469993277673
12193a45430bb8
13976578b0a7a
1447c8082720c
152451c915b22
hex133623cf9bc

1320203123132 has 12 divisors (see below), whose sum is σ = 2312161850880. Its totient is φ = 659585451456.

The previous prime is 1320203123053. The next prime is 1320203123143. The reversal of 1320203123132 is 2313213020231.

It is a junction number, because it is equal to n+sod(n) for n = 1320203123098 and 1320203123107.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129021773 + ... + 129032004.

It is an arithmetic number, because the mean of its divisors is an integer number (192680154240).

Almost surely, 21320203123132 is an apocalyptic number.

It is an amenable number.

1320203123132 is a deficient number, since it is larger than the sum of its proper divisors (991958727748).

1320203123132 is a wasteful number, since it uses less digits than its factorization.

1320203123132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 258055060 (or 258055058 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1320203123132 its reverse (2313213020231), we get a palindrome (3633416143363).

The spelling of 1320203123132 in words is "one trillion, three hundred twenty billion, two hundred three million, one hundred twenty-three thousand, one hundred thirty-two".

Divisors: 1 2 4 1279 2558 5116 258053777 516107554 1032215108 330050780783 660101561566 1320203123132