1320204120101 has 4 divisors (see below), whose sum is σ = 1320260030112. Its totient is φ = 1320148210092.

The previous prime is 1320204120077. The next prime is 1320204120133. The reversal of 1320204120101 is 1010214020231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320204120101 - 2¹⁰ = 1320204119077 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1320204120101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320204120701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27919571 + ... + 27966816.

It is an arithmetic number, because the mean of its divisors is an integer number (330065007528).

Almost surely, 2^{1320204120101} is an apocalyptic number.

It is an amenable number.

1320204120101 is a deficient number, since it is larger than the sum of its proper divisors (55910011).

1320204120101 is an equidigital number, since it uses as much as digits as its factorization.

1320204120101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55910010.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1320204120101 its reverse (1010214020231), we get a palindrome (2330418140332).

The spelling of 1320204120101 in words is "one trillion, three hundred twenty billion, two hundred four million, one hundred twenty thousand, one hundred one".