Base | Representation |
---|---|
bin | 11110000001001001101101… |
… | …011101111010000101101111 |
3 | 122022110001002111221100111122 |
4 | 132001021231131322011233 |
5 | 114301011032033113403 |
6 | 1144441222134211155 |
7 | 36544112041325000 |
oct | 3601115535720557 |
9 | 568401074840448 |
10 | 132020541301103 |
11 | 3907a662883614 |
12 | 129825701b3abb |
13 | 58886396aa0a0 |
14 | 2485b84b9b1a7 |
15 | 103e255ab7838 |
hex | 78126d77a16f |
132020541301103 has 32 divisors (see below), whose sum is σ = 165817779792000. Its totient is φ = 104446424533248.
The previous prime is 132020541301013. The next prime is 132020541301109. The reversal of 132020541301103 is 301103145020231.
It is not a de Polignac number, because 132020541301103 - 210 = 132020541300079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132020541301109) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 48495443 + ... + 51145371.
It is an arithmetic number, because the mean of its divisors is an integer number (5181805618500).
Almost surely, 2132020541301103 is an apocalyptic number.
132020541301103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
132020541301103 is a deficient number, since it is larger than the sum of its proper divisors (33797238490897).
132020541301103 is a wasteful number, since it uses less digits than its factorization.
132020541301103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2661136 (or 2661122 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 132020541301103 its reverse (301103145020231), we get a palindrome (433123686321334).
The spelling of 132020541301103 in words is "one hundred thirty-two trillion, twenty billion, five hundred forty-one million, three hundred one thousand, one hundred three".
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